-8x^2+6+22x=0

Solution for -8x^2+6+22x=0 equation:

-8x^2+6+22x=0

a = -8; b = 22; c = +6;
Δ = b2-4ac
Δ = 222-4·(-8)·6
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-26}{2*-8}=\frac{-48}{-16}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+26}{2*-8}=\frac{4}{-16}
=-1/4
$